Banking exams quant section formula sheet

bankingexamsquantitativeapitiude
Image source: Pixabay

In today’s article we are going to cover some essential formulae required for solving quantitative section of popular banking exams like SBI PO,IBPS PO among others.

    • Number systems and Simplification

Divisibility rules of…

2: last digit is even or 0 4: last two digits are divisible by 4 8: last 3 digits are divisible by 8
3: Sum of digits is divisible by 3 6:Number is simultaneously divisible by 2 &3  9: Sum of digits is divisible by 9
5: last digit is 5 or 0 10: last digit is 0  15:If the number is divisible by 3 and 5
 7: Unit’s place is multiplied by 2 and subtracted from the remaining digits and no obtained is divisible by 7 17: Unit’s place is multiplied by 5 and subtracted from the remaining digits and the number obtained is divisible by 17  14: If the number is divisible by 2 and 7
11: Sum of digit’s at odd and even places are subtracted and the result is either 0 or the no obtained is divisible by 11 12: If it is divisible by 4 and 3  18: If it is divisible by 2 and 9
13: If it’s unit place is multiplied by 4 and added to remaining digits and no obtained is divisible by 13 19:  If it’s unit place is multiplied by 2 and added to remaining digits and no obtained is divisible by 19

 

 

Examples:

1)Is 2289 divisible by 7?

Ans: 1st pass: 228 – (9 x 2) = 210

2nd pass: 21 – 0  = 21

21 is divisible by 7, hence 2289 is divisible by 7

2)Is 156 divisible by 13?

Ans: 1st pass: 15 + (4 x 6) = 15 + 24 = 39

39 is divisible by 13, hence 156 is divisible by 13

Sum series:

Sum of first n natural nos = \frac{n(n+1)}{2}

Sum of first n2 natural numbers = \frac{n(n+1)(2n+1)}{6}

Sum of first n natural numbers =  \frac{n^{2}(n+1)^{2}}{4}

Division Algorithm:

Dividend = (Divisor x Quotient) + Remainder

Total number of different divisors of a number X:

Step 1: Find all the possible prime factors of X

X = ax + by + cz   + …

Step 2: Total number of divisors:

=(x + 1)(y + 1)(z+1)….

Example:

Question:Find total number of divisors of 15:

Ans:16 =  24

The total number of divisors of 16 = (4+1) = 5

If we check through normal way, divisors of 16 are (1,2,4,8,16) i.e. the count is 5

Average

Average/mean = \frac{Sum of all entities}{Number of entities}

When one quantity is added or removed from average:

Sum of added/removed quantities = [Change in number of original quantities x original average] \pm [change in average x final no. of quantities]

Ex. The average weight of 25 apples is 8kg. If 5 new apples are added then average is increased by 0.6kg. Find average of new apples.

Sum of weights added = [5(change in quantity) x 8(original average)] + [0.6(change in average) x 30(final no. of quantities)]

=  40 + 18 = 58kg

Average of 5 new apples = \frac{58}{5}

= 11.6 kg

If a part of journey is covered a kmph and equal distance at b kmph then average speed of whole journey

= \frac{2ab}{a + b}

That’s for today’s short article. We will cover more formulae in the next post.

Connect Deeper:

In the next article we will try to cover more formulas on percentage and ratio & proportion. In order to get notified follow us on facebook: Technoetics or subscribe to our mailing list below:

Technoetics newsletter

Get notified about upcoming articles,tips and tricks personally hand-delivered to your inbox

 

Share post-
About Saurabh Mhatre 70 Articles
Currently working in web and hybrid application development